use_of_void_result
This expression has a type of 'void' so its value can't be used.
Description
#The analyzer produces this diagnostic when it finds an expression whose type is void
, and the expression is used in a place where a value is expected, such as before a member access or on the right-hand side of an assignment.
Example
#The following code produces this diagnostic because f
doesn't produce an object on which toString
can be invoked:
void f() {}
void g() {
f().toString();
}
Common fixes
#Either rewrite the code so that the expression has a value or rewrite the code so that it doesn't depend on the value.
Unless stated otherwise, the documentation on this site reflects Dart 3.7.3. Page last updated on 2025-05-08. View source or report an issue.