type_test_with_non_type
The name '{0}' isn't a type and can't be used in an 'is' expression.
Description
#The analyzer produces this diagnostic when the right-hand side of an is
or is!
test isn't a type.
Example
#The following code produces this diagnostic because the right-hand side is a parameter, not a type:
typedef B = int Function(int);
void f(Object a, B b) {
if (a is b) {
return;
}
}
Common fixes
#If you intended to use a type test, then replace the right-hand side with a type:
typedef B = int Function(int);
void f(Object a, B b) {
if (a is B) {
return;
}
}
If you intended to use a different kind of test, then change the test:
typedef B = int Function(int);
void f(Object a, B b) {
if (a == b) {
return;
}
}
Unless stated otherwise, the documentation on this site reflects Dart 3.7.3. Page last updated on 2025-05-08. View source or report an issue.